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(A) To expand $(2x - y + z)^2$,we use the algebraic identity: $(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$.Here,$a = 2x$,$b = -y$,and $c = z$.S

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$4x^2 + y^2 + z^2 - 4xy - 2yz + 4zx$

Vedclass · Answer

(A) To expand $(2x - y + z)^2$,we use the algebraic identity: $(a + b + c)^2 = a^2 + b^2 + c^2 + 2ab + 2bc + 2ca$.Here,$a = 2x$,$b = -y$,and $c = z$.Substituting these values into the identity:$(2x - y + z)^2 = (2x)^2 + (-y)^2 + (z)^2 + 2(2x)(-y) + 2(-y)(z) + 2(z)(2x)$Calculating each term:$(2x)^2 = 4x^2$$(-y)^2 = y^2$$(z)^2 = z^2$$2(2x)(-y) = -4xy$$2(-y)(z) = -2yz$$2(z)(2x) = 4zx$Combining these,we get:$(2x - y + z)^2 = 4x^2 + y^2 + z^2 - 4xy - 2yz + 4zx$.

Expand each of the following,using suitable identities: $(2x - y + z)^2$

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